Primary 3 Mathematics Semestral Assessment 2 (End of Year) Paper 4

TuitionGoWhere Practice Paper - Mathematics Primary 3

Whole Numbers Topic Quiz - SA2 Version 4 — Answer Key & Marking Scheme

Total Marks: 50

Section A (Questions 1-5) — 10 marks

Q1 (2 marks): B (4) Place value tells us what each digit position means. Reading 8 406 from the left: 8 is in the thousands place, 4 is in the hundreds place, 0 is in the tens place, 6 is in the ones place. The hundreds digit is 4. Common mistake: Choosing C (0) by miscounting positions from the wrong end. Always name places from the right: ones, tens, hundreds, thousands.

Q2 (2 marks): C (700) The digit 7 sits in the hundreds place of 5 731, so its value is 7 × 100 = 700. Key idea: The digit is 7, but the value of the digit depends on its place. This distinction is tested often.

Q3 (2 marks): C (6 980) All four numbers have 6 thousands, so compare the hundreds digit: 0, 8, 9, 9. The two largest are 6 980 and 6 908. Then compare tens: 8 tens beats 0 tens, so 6 980 is greatest.

Q4 (2 marks): C (2 900) Find the rule first: 2 400 − 2 150 = 250 and 2 650 − 2 400 = 250. The pattern adds 250 each time. Missing term = 2 650 + 250 = 2 900. Check: 2 900 + 250 = 3 150 ✓.

Q5 (2 marks): A (Nine thousand and eighty) 9 080 has 9 thousands, 0 hundreds, 8 tens, 0 ones. We read the 8 as "eighty" because it is in the tens place. Common mistake: Option B ignores the 0 in the hundreds place; option C invents extra digits. When a middle place is 0, say "and" or skip cleanly without renaming the place.

Section B (Questions 6-15) — 20 marks

Q6 (2 marks): 7 306 Build the number place by place: seven thousand → 7___; three hundred → 73__; no tens → 730_; six ones → 7 306. [M1: correct places identified; A1: 7 306] Common mistake: Writing 7 036 (swapping hundreds and tens) or 7 360.

Q7 (2 marks): Six thousand, two hundred and fifty Read each nonzero place: 6 thousands, 2 hundreds, 5 tens. The 0 in the ones place is simply not named. [A1 per correct half: "six thousand, two hundred" and "fifty"]

Q8 (2 marks): 4 829, 4 892, 4 928, 4 982 All have 4 thousands, so compare hundreds: 8, 8, 9, 9. Group (4 829, 4 892) before group (4 928, 4 982). Within each pair, compare tens: 2 < 9. Ascending order follows. [M1: correct grouping by hundreds; A1: full correct order]

Q9 (2 marks): 7 900 Rule: each term decreases by 300 (8 500 − 8 200 = 300; 7 600 − 7 300 = 300). Missing term = 8 200 − 300 = 7 900. Check: 7 900 − 300 = 7 600 ✓.

Q10 (2 marks): 2 058 Read bead counts against the labels: Thousands rod = 2, Hundreds rod = 0, Tens rod = 5, Ones rod = 8. Write the counts in order: 2 058. Expected visual (Q10-fig1): four labelled rods with bead counts 2, 0, 5, 8 and an empty Hundreds rod. Common mistake: Writing 258 (skipping the empty place). Every place must show a digit, even 0.

Q11 (2 marks): 6 500 To round to the nearest hundred, look at the tens digit of 6 472. The tens digit is 7, and 7 ≥ 5, so round the hundreds digit up: 4 becomes 5. Replace the tens and ones with zeros: 6 500. [M1: correct decision using the tens digit; A1: 6 500]

Q12 (2 marks): 2 057 To make the smallest 4-digit number, put the smallest available digit in the thousands place — but it cannot be 0 (then it would not be a 4-digit number). So thousands = 2. Arrange the rest from smallest to largest: 0, 5, 7. Answer: 2 057. [M1: nonzero thousands digit chosen; A1: 2 05

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# TuitionGoWhere Practice Paper - Mathematics Primary 3

## Whole Numbers Topic Quiz - SA2 Version 4 — Answer Key & Marking Scheme

**Total Marks:** 50

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## Section A (Questions 1-5) — 10 marks

**Q1 (2 marks): B (4)**
Reading 8 406 from the right: ones = 6, tens = 0, hundreds = 4, thousands = 8. The hundreds digit is 4.
*Common mistake:* Choosing C (0) by counting places from the wrong end.

**Q2 (2 marks): C (700)**
The digit 7 sits in the hundreds place of 5 731, so its value is 7 × 100 = 700.
*Key idea:* The **digit** is 7, but its **value** depends on its place.

**Q3 (2 marks): C (6 980)**
All four numbers have 6 thousands, so compare hundreds: 0, 8, 9, 9. The two largest are 6 980 and 6 908; compare tens: 8 > 0, so 6 980 is greatest.

**Q4 (2 marks): C (2 900)**
Rule: 2 400 − 2 150 = 250 and 2 650 − 2 400 = 250, so the pattern adds 250 each time. Missing term = 2 650 + 250 = 2 900. Check: 2 900 + 250 = 3 150 ✓.

**Q5 (2 marks): A (Nine thousand and eighty)**
9 080 has 9 thousands, 0 hundreds, 8 tens, 0 ones. The 8 is read as "eighty" because it is in the tens place.
*Common mistake:* Option B ignores the 0 in the hundreds place.

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## Section B (Questions 6-15) — 20 marks

**Q6 (2 marks): 7 306**
Seven thousand → 7___; three hundred → 73__; no tens → 730_; six ones → 7 306. [M1: correct places; A1: 7 306]
*Common mistake:* Writing 7 036 or 7 360.

**Q7 (2 marks): Six thousand, two hundred and fifty**
6 thousands, 2 hundreds, 5 tens; the 0 in the ones place is not named. [A1 per correct half]

**Q8 (2 marks): 4 829, 4 892, 4 928, 4 982**
All have 4 thousands; group by hundreds: (4 829, 4 892) before (4 928, 4 982); within pairs compare tens: 2 < 9. [M1: grouping; A1: order]

**Q9 (2 marks): 7 900**
Each term decreases by 300 (8 500 − 8 200 = 300; 7 600 − 7 300 = 300). Missing term = 8 200 − 300 = 7 900. Check: 7 900 − 300 = 7 600 ✓.

**Q10 (2 marks): 2 058**
Thousands rod = 2, Hundreds rod = 0, Tens rod = 5, Ones rod = 8 → 2 058.
*Common mistake:* Writing 258 and skipping the empty Hundreds place. Every place needs a digit, even 0.

**Q11 (2 marks): 6 500**
Look at the tens digit of 6 472: it is 7, and 7 ≥ 5, so round up. Hundreds digit 4 becomes 5; replace tens and ones with zeros → 6 500. [M1: decision rule; A1: 6 500]

**Q12 (2 marks): 2 057**
For the smallest 4-digit number, the thousands digit must be the smallest nonzero digit: 2. Arrange the rest smallest to largest: 0, 5, 7 → 2 057. [M1: nonzero thousands digit; A1: 2 057]
*Common mistake:* Writing 0257, which is not a 4-digit number.

**Q13 (2 marks): <**
Compare 7 098 and 7 100: same thousands (7); hundreds: 0 < 1, so 7 098 < 7 100.

**Q14 (2 marks): 5 999**
1 less than 6 000 requires regrouping across all places: 6 000 − 1 = 5 999.
*Common mistake:* Writing 5 000 or 6 001.

**Q15 (2 marks): 3 480**
Even numbers end in 0, 2, 4, 6 or 8. From the list, only 3 480 and 3 408 are even; 3 485 and 3 845 end in 5 (odd). Comparing 3 480 and 3 408: 8 tens > 0 tens, so 3 480 is the largest even number.

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## Section C (Questions 16-20) — 20 marks

**Q16 (4 marks): Aisha is correct.**
In 7 384, the digit 3 is in the **hundreds** place (7 thousands, 3 hundreds, 8 tens, 4 ones). Its value is 3 × 100 = 300. Ben's claim of 30 would only be true if the 3 were in the tens place. [M1: identifies hundreds place; M1: computes 300; A1: names Aisha; A1: clear explanation]

**Q17 (4 marks): 220 parking lots**
Level 1: 120; Level 2: 120 + 25 = 145; Level 3: 145 + 25 = 170; Level 4: 170 + 25 = 195; Level 5: 195 + 25 = 220. [M1: pattern +25 recognised; M1: working shown; A1: 220; A1: units/statement]
Answer: **220 parking lots**

**Q18 (4 marks): (a) 8 316  (b) 1 683**
(a) Greatest even: the ones digit must be even (6 or 8). Trying ones = 6 gives 8 316; trying ones = 8 gives at best 6 318. Largest is **8 316**.
(b) Smallest odd: the ones digit must be odd (1 or 3). Trying ones = 3 gives 1 683; trying ones = 1 gives at best 3 681. Smallest is **1 683**. [M1 per part for reasoning about the ones digit; A1 per part]

**Q19 (4 marks):**
(a) Most to least: 2 770 (3D), 2 750 (3A), 2 705 (3B), 2 577 (3C).
(b) Third-highest is 2 705, so class **3B** wins the bookmark voucher. [M1: comparison strategy; A1: part (a) order; A1: part (b); A1: working shown]

**Q20 (4 marks):**
(a) Nearest hundred: look at the tens digit of 4 628 — it is 2, and 2 < 5, so round down → **4 600 seats**.
(b) Nearest thousand: look at the hundreds digit — it is 6, and 6 ≥ 5, so round up → **5 000 seats**. [M1 per part: correct digit checked; A1 per part]

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