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O Level Physics Waves Sound Light Quiz

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O Level Physics AI Generated Generated by Qwen3.6 Plus Updated 2026-08-17

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Answers

O-Level Physics Quiz - Waves Sound Light (Answer Key)

Total Marks: 40

Section A: General Properties of Waves & Sound

1.
(a) A wave in which the particles of the medium vibrate perpendicular (at right angles) to the direction of wave energy propagation. [1]
(b) Light / Electromagnetic waves / Water waves (surface). [1]

2.
(a) Wavelength = distance between two consecutive peaks or equivalent points. From graph (0 to 8m is one full cycle? No, 0 to 4 is half. 0 to 8 is full). Wavelength = 8 m. [1]
(b) Amplitude = maximum displacement from equilibrium. Amplitude = 0.5 m. [1]

3.
(a) v=fλv = f \lambda
v=250×1.36v = 250 \times 1.36
v=340 m/sv = 340 \text{ m/s} [2] (1 mark for formula/substitution, 1 for answer)
(b) Frequency: Stays the same (unchanged). [1]
Wavelength: Increases (because speed increases and v=fλv=f\lambda). [1]

4.

  • The source vibrates, causing air particles to vibrate/oscillate. [1]
  • This creates regions of high pressure/density called compressions and regions of low pressure/density called rarefactions. [1]
  • These compressions and rarefactions propagate through the medium, transferring energy without transferring matter. [1]

5.

  • Distance travelled by sound = speed ×\times time
  • dtotal=1500×0.80=1200 md_{total} = 1500 \times 0.80 = 1200 \text{ m} [1]
  • This is the distance down and back (2 ways). [1]
  • Depth = 1200/2=600 m1200 / 2 = 600 \text{ m}. [1]

6.
(a) Interference (or Superposition). [1]
(b) Quiet sounds occur due to destructive interference. [1]
This happens when a compression from one speaker meets a rarefaction from the other (or waves are 180180^\circ out of phase), cancelling each other out. [1]

7.
Answer: B (Frequency). [1]


Section B: Light and Electromagnetic Spectrum

8.
(a) A: Infrared [1]
B: X-rays [1]
(b) Any two of: [2]

  • Travel at the speed of light (3.0×108 m/s3.0 \times 10^8 \text{ m/s}) in vacuum.
  • Are transverse waves.
  • Can travel through a vacuum (do not require a medium).
  • Can be reflected, refracted, diffracted, and polarized.

9.
(a) Ray drawn reflecting off the mirror such that the angle with the normal is equal to the incident angle. [1]
(b) Angle of reflection = 40 ^\circ. [1]

10.
(a) n=sinisinrn = \frac{\sin i}{\sin r}
n=sin30sin19n = \frac{\sin 30^\circ}{\sin 19^\circ}
n=0.50.32561.535n = \frac{0.5}{0.3256} \approx 1.535
Refractive index = 1.54 (or 1.5). [2]
(b) sinc=1n\sin c = \frac{1}{n}
sinc=11.535\sin c = \frac{1}{1.535}
c=sin1(0.651)c = \sin^{-1}(0.651)
Critical angle = 40.6 ^\circ (accept 40-41). [2]

11.
(a) The ray enters along the normal (perpendicular to the surface), so the angle of incidence is 00^\circ. Therefore, there is no refraction (light does not bend). [1]
(b) The angle of incidence (4545^\circ) is greater than the critical angle (4242^\circ). [1]
Therefore, Total Internal Reflection occurs. [1]
The ray is reflected back into the glass block at an angle of reflection of 4545^\circ. [1]

12.
(a) Total Internal Reflection. [1]
(b) Any one: [1]

  • Higher bandwidth / carries more data.
  • Less signal loss / attenuation over long distances.
  • Immune to electromagnetic interference.
  • Lighter and thinner than copper.

13.
(a) Object is at 15 cm15 \text{ cm}, F=10 cmF=10 \text{ cm}. Object is between FF and 2F2F.
Image characteristics:

  1. Real [1]
  2. Inverted [1]
  3. Magnified [1]
    (b) Projector / Slide projector / Cinema projector. [1]

14.
Answer: B (Infrared). [1]


Section C: Structured Problems & Applications

15.
(a) Draw a normal line perpendicular to the surface at the point of entry. Measure the angle between the refracted ray and the normal using a protractor. [2]
(b) The angle of refraction becomes smaller. [1]
Explanation: A higher refractive index means light slows down more, causing it to bend more towards the normal. [1]

16.
(a) Ray Diagram: [3]

  1. Ray parallel to principal axis refracts through the principal focus FF on the other side. [1]
  2. Ray through the optical center passes undeviated. [1]
  3. The rays diverge on the right side. They must be traced back (dashed lines) to the left to find where they appear to meet. [1]
    (b) Nature of image: Virtual, Upright, Magnified. (Any two for 2 marks, or 1 mark for correct general description). [2]

17.
(a) v=fλf=v/λv = f \lambda \Rightarrow f = v / \lambda
f=3.0×1080.03f = \frac{3.0 \times 10^8}{0.03}
f=3.0×1083.0×102f = \frac{3.0 \times 10^8}{3.0 \times 10^{-2}}
f=1.0×1010 Hzf = 1.0 \times 10^{10} \text{ Hz}. [3] (1 mark formula, 1 mark substitution, 1 mark answer)
(b) Microwaves. [1]

18.
Sound is a mechanical wave that requires a medium (particles) to travel. [1]
Space is a vacuum (has no particles/air), so sound cannot propagate. [1]

19.
(a) Ray Diagram: [3]

  1. Horizontal ray enters top, hits top mirror. [1]
  2. Reflects downwards (angle i=r=45i=r=45^\circ). [1]
  3. Hits bottom mirror, reflects horizontally out to eye. [1]
    (b) The image is upright (and laterally inverted, but upright is the key feature for seeing over obstacles). [1]

20.
(a) Dispersion. [1]
(b) Violet light has a higher frequency / shorter wavelength than red light. [1]
Therefore, violet light travels slower in glass and is refracted (bent) more than red light. [1]