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O Level Geography Practice Paper 5

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TuitionGoWhere Practice Paper - Geography O-Level

TuitionGoWhere Practice Paper (AI)

Subject: Geography (2279)
Level: O-Level
Paper: Practice Paper – Map, Graph & Data Skills (Version 5 of 5)
Duration: 1 Hour
Total Marks: 40

Name: ________________________
Class: ________________________
Date: ________________________

Instructions to Candidates

Answer all questions.
Write your answers in the spaces provided.
You may use a calculator for any calculations.
Marks are indicated in brackets [ ] at the end of each question or part question.
This paper focuses on Map, Graph, and Data Skills (AO2) and their application to geographical contexts.

Section A: Map Reading and Spatial Analysis

Study the extract of a topographical map (1:25,000 scale) of a coastal region below. (Note: In a real exam, a map extract would be provided. For this practice, assume the following grid references and features exist.)

Grid Square 4512: Contains a school and a post office.
Grid Square 4613: Contains a steep slope with contour lines close together, rising from 20m to 80m.
Grid Square 4714: Contains a mangrove swamp and a river mouth.
Spot Height 88: Located at 462135.
Benchmark 25: Located at 455125.

1. Calculate the straight-line distance in kilometers between the Post Office (4512) and Spot Height 88 (462135). Show your working. [2]

2. Describe the relief characteristics of the area in Grid Square 4613. Refer to contour patterns and height in your answer. [3]

3. A student wants to measure the sinuosity of the river in Grid Square 4714. (a) Define sinuosity. [1]

(b) Describe the method the student should use to measure the length of the meandering river channel on the map. [2]

4. The map shows a mangrove swamp in Grid Square 4714. (a) Identify two map symbols or features that typically indicate a mangrove or swampy area on a topographical map. [2]

(b) Explain why it might be difficult to conduct fieldwork in this specific grid square. [2]

5. Calculate the gradient between Benchmark 25 (455125) and Spot Height 88 (462135).

Vertical Interval (VI) = ______ m
Horizontal Equivalent (HE) = ______ km (convert to meters)
Gradient = ______ [3]

Section B: Graphical Representation and Data Processing

Study Table 1, which shows the monthly rainfall and temperature data for Station A.

Month	Jan	Feb	Mar	Apr	May	Jun	Jul	Aug	Sep	Oct	Nov	Dec
Temp (°C)	26	27	28	29	29	28	27	27	27	27	26	26
Rainfall (mm)	240	210	180	150	120	100	90	110	140	190	230	250

6. Calculate the annual range of temperature for Station A. [1]

7. Calculate the total annual rainfall for Station A. [1]

8. Suggest the most appropriate type of graph to display both the temperature and rainfall data on a single chart. Explain your choice. [3]

9. A student collects noise level data (in decibels, dB) at five different sites in a city center. The results are:

Site 1 (Park): 45 dB
Site 2 (Main Road): 78 dB
Site 3 (Shopping Mall Entrance): 65 dB
Site 4 (Residential Street): 52 dB
Site 5 (Bus Interchange): 82 dB

(a) Calculate the mean noise level across all five sites. Show your working. [2]

(b) Identify the mode of the data set, if any. If there is no mode, state "No mode". [1]

10. The student decides to present the noise level data using a divided bar graph. (a) Explain why a divided bar graph is not suitable for this specific data set. [2]

(b) Suggest a more suitable graphical representation for comparing noise levels across these distinct sites. [1]

11. Study the scatter graph below (described):

X-axis: Distance from City Center (km)
Y-axis: Land Value ($ per sq meter)
The points show a strong negative correlation.

(a) Describe the relationship shown in the scatter graph. [2]

(b) Suggest one reason for this relationship. [1]

12. A group of students conducts a pedestrian count. They record the number of people passing a point every 10 minutes for one hour.

09:00-09:10: 15 people
09:10-09:20: 22 people
09:20-09:30: 45 people
09:30-09:40: 38 people
09:40-09:50: 20 people
09:50-10:00: 18 people

(a) Calculate the median number of pedestrians per 10-minute interval. [2]

(b) Why might the mean be a less reliable measure of central tendency if one interval had an unusually high count (e.g., due to a bus arrival)? [2]

Section C: Fieldwork Data Evaluation and Interpretation

Context: Students are investigating the hypothesis: "Water quality decreases as distance downstream from a factory increases." They measure pH levels and turbidity (cloudiness) at 5 sites.

Table 2: Water Quality Data

Site	Distance from Factory (km)	pH Level	Turbidity (NTU)
1	0.5	7.0	5
2	1.0	6.8	12
3	2.0	6.5	25
4	3.0	6.2	40
5	4.0	6.0	55

13. Plot the relationship between Distance from Factory and Turbidity on the grid below. Label axes appropriately. [4]

(Imagine a blank grid here. Student must sketch axes and plot points.)

14. Based on Table 2, describe the trend in pH levels as distance from the factory increases. [2]

15. The students used a digital pH meter for data collection. (a) Identify one advantage of using a digital pH meter over universal indicator paper. [1]

(b) Identify one limitation of using a digital pH meter in the field. [1]

16. Evaluate the reliability of the conclusion that "the factory is causing the water pollution." Refer to the data and methodology in your answer. [4]

17. The students want to improve the validity of their investigation. Suggest two additional variables they should control or measure to ensure their results are valid. [2]

18. A second group of students investigates beach sediment size. They use a calliper to measure the long axis of 50 pebbles at Site A. (a) Why is it important to measure a large sample size (e.g., 50 pebbles) rather than just 5? [2]

(b) Describe how they should process the raw data to find the mean sediment size. [2]

19. Study the rose diagram below (described):

The diagram shows wind direction frequency.
The longest arm points to the North-East.
The shortest arm points to the South-West.

(a) What is the prevailing wind direction shown in the diagram? [1]

(b) How does a rose diagram differ from a simple bar chart when displaying wind data? [2]

20. A student presents data on population growth using a pie chart. Critique this choice of graphical representation. Suggest a better alternative and explain why. [3]

End of Paper

Answers

TuitionGoWhere Practice Paper - Geography O-Level

Answer Key & Marking Scheme Paper: Practice Paper – Map, Graph & Data Skills (Version 5 of 5)

Section A: Map Reading and Spatial Analysis

1. Calculate straight-line distance.

Working:
- Grid Reference 1: 4512 (Center approx 455125)
- Grid Reference 2: 462135
- Difference in Eastings: $462 - 455 = 7$ units ( $7 \times 100m = 700m$ )
- Difference in Northings: $135 - 125 = 10$ units ( $10 \times 100m = 1000m$ )
- Pythagoras: $\sqrt{700^2 + 1000^2} = \sqrt{490000 + 1000000} = \sqrt{1490000} \approx 1220m$
- Alternative Simple Method (if measuring directly on map with ruler): Measure cm, multiply by scale factor.
- Note for marking: Accept answers between 1.2 km and 1.3 km depending on precise point selection within grid squares.
Answer: ~1.22 km (or 1220 m).
Marks: [1] for correct working/method, [1] for correct answer with units.

2. Describe relief in Grid Square 4613.

Answer:
- The area is steep/hilly. [1]
- Contour lines are close together, indicating a steep gradient. [1]
- Height increases from 20m to 80m (or similar range based on contours). [1]
Marks: [3]

3. River Sinuosity.

(a) Define sinuosity: The ratio of the channel length to the straight-line valley length (or a measure of how much a river meanders). [1]
(b) Method:
- Use a piece of string/thread to trace the center of the river channel from start to end point. [1]
- Straighten the string and measure its length against the map scale (ruler). [1]
Marks: [1] + [2]

4. Mangrove Swamp.

(a) Symbols:
- Green shading/tinting (vegetation). [1]
- Specific symbol for swamp/marsh (often tufts of grass or blue/green mix). [1]
- Accept: Contour lines showing very flat land (0-5m) near coast.
(b) Difficulty:
- Soft/muddy ground makes walking difficult/dangerous (sinking). [1]
- Dense vegetation limits visibility/access. [1]
- Accept: Presence of wildlife/insects, tidal risks.
Marks: [2] + [2]

5. Calculate Gradient.

VI: $88m - 25m = 63m$ . [1]
HE: Distance calculated in Q1 (approx 1220m). Note: If student uses different points, follow through. Let's assume HE is 1220m. [1]
Gradient: $63 / 1220 \approx 1$ $63/1220 \approx 1$ in $19.3$ $19.3$ .
- Formula: $VI / HE$ . [1]
Marks: [3] (1 for VI, 1 for HE, 1 for correct ratio format).

Section B: Graphical Representation and Data Processing

6. Annual Range of Temperature.

Calculation: Max Temp ( $29^\circ C$ ) - Min Temp ( $26^\circ C$ ) = $3^\circ C$ .
Marks: [1]

7. Total Annual Rainfall.

Calculation: $240+210+180+150+120+100+90+110+140+190+230+250 = 2010 mm$ .
Marks: [1]

8. Graph Type Suggestion.

Answer: Climate Graph (or Combination Graph). [1]
Explanation: It allows simultaneous display of two different data types (temperature as line graph, rainfall as bar chart) on the same x-axis (time/months) to show relationships/seasonality. [2]
Marks: [3]

9. Noise Level Data.

(a) Mean:
- Sum: $45+78+65+52+82 = 322$ .
- Count: 5.
- Mean: $322 / 5 = 64.4 dB$ .
- Marks: [1] for sum, [1] for division/answer.
(b) Mode:
- Answer: No mode (all values appear only once). [1]
Marks: [1]

10. Divided Bar Graph Critique.

(a) Why unsuitable: Divided bar graphs are used to show parts of a whole (percentages/composition) for a single entity or comparison of compositions. Noise levels are absolute values for distinct categories, not parts of a total. [2]
(b) Better Alternative: Bar Chart (or Column Graph). [1]
Marks: [2] + [1]

11. Scatter Graph.

(a) Relationship: Strong negative correlation. As distance from city center increases, land value decreases. [2]
(b) Reason: Land is scarcer/more accessible in CBD; demand is higher in center. [1]
Marks: [2] + [1]

12. Pedestrian Count.

(a) Median:
- Order data: 15, 18, 20, 22, 38, 45.
- Middle two values: 20 and 22.
- Average: $(20+22)/2 = 21$ .
- Marks: [2]
(b) Mean Reliability:
- The mean is sensitive to outliers/extreme values. A single bus arrival (spike) would skew the mean higher, making it unrepresentative of the "typical" flow. [2]
Marks: [2]

Section C: Fieldwork Data Evaluation and Interpretation

13. Plotting Graph.

Requirements:
- X-axis labeled "Distance from Factory (km)" with scale 0-5. [1]
- Y-axis labeled "Turbidity (NTU)" with appropriate scale. [1]
- All 5 points plotted correctly. [1]
- Line of best fit or straight lines connecting points. [1]
Marks: [4]

14. pH Trend.

Answer: pH levels decrease (become more acidic) as distance from the factory increases. [1]
Data Ref: From 7.0 at 0.5km to 6.0 at 4.0km. [1]
Marks: [2]

15. Digital pH Meter.

(a) Advantage: More precise/accurate reading (decimal places) than color matching. [1]
(b) Limitation: Requires batteries/calibration; fragile; can be affected by temperature. [1]
Marks: [1] + [1]

16. Evaluate Reliability of Conclusion.

Answer Points:
- Support: Data shows clear trend (correlation) between distance and pollution indicators (pH/turbidity). [1]
- Limitation 1: Correlation does not prove causation. Other sources (agricultural runoff, sewage) could exist downstream. [1]
- Limitation 2: Only 5 sites sampled; small sample size may miss variations. [1]
- Limitation 3: Single visit (time of day/weather not controlled) affects reliability. [1]
Marks: [4] (1 per valid point, max 4).

17. Improve Validity.

Suggestions:
- Control for rainfall (test only on dry days to avoid dilution). [1]
- Measure flow rate/velocity (pollutant concentration depends on volume). [1]
- Accept: Test for specific chemicals (nitrates/phosphates) to link to factory type.
Marks: [2]

18. Sediment Sample Size.

(a) Importance: Reduces the impact of anomalies/outliers; provides a more representative average of the beach material. [2]
(b) Processing: Sum of all 50 measurements divided by 50. [2]
Marks: [2] + [2]

19. Rose Diagram.

(a) Prevailing Wind: North-East. [1]
(b) Difference: Rose diagram shows directionality and frequency simultaneously in a circular format, which is intuitive for wind data. A bar chart would require 8-16 separate bars and loses the spatial "compass" context. [2]
Marks: [1] + [2]

20. Pie Chart Critique.

Critique: Pie charts are for showing proportions of a whole at a single point in time. Population growth is a time-series (change over time). [1]
Alternative: Line Graph. [1]
Reason: Line graphs clearly show trends, rates of change, and continuous data over time. [1]
Marks: [3]