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O Level Elementary Mathematics Algebra Functions Quiz

Free O Level E Maths Algebra Functions quiz, Gemma31B Exam version, with questions, answers, and O Level-style practice for Singapore students.

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O Level Elementary Mathematics From Real Exams Generated by Gemma 4 31B Updated 2026-08-17

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Questions

O-Level Elementary Mathematics Quiz - Algebra Functions

Name: ____________________
Class: ____________________
Date: ____________________
Score: ________ / 45

Duration: 60 Minutes
Total Marks: 45

Instructions:

Answer all questions.
Show all necessary working.
Give your answers to 3 significant figures where applicable.
Use of an approved scientific calculator is allowed.

Section A: Basic Algebraic Manipulation (Questions 1–8)

Focus: Expansion, Factorisation, and Simplification

Factorise completely: $12x^2y - 18xy^2$ .

Answer: ____________________ [1]
Expand and simplify: $(3a - 4b)^2$ .

Answer: ____________________ [2]
Factorise completely: $4x^2 - 25$ .

Answer: ____________________ [1]
Simplify the expression: $\frac{6p^2q}{3pq^3}$ .

Answer: ____________________ [1]
Factorise completely: $2x^2 - 7x - 15$ .

Answer: ____________________ [2]
Expand and simplify: $(2x + 3)(x - 5)$ .

Answer: ____________________ [2]
Simplify: $\frac{x}{3} + \frac{x-2}{4}$ .

Answer: ____________________ [2]
Factorise completely: $3ax - 3ay - bx + by$ .

Answer: ____________________ [2]

Section B: Equations and Formulae (Questions 9–15)

Focus: Solving Equations and Changing Subjects

Solve for $x$ : $4(x - 3) = 2x + 7$ .

Answer: ____________________ [2]
Make $t$ the subject of the formula: $V = u t + \frac{1}{2} a t^2$ , given that $u = 0$ .

Answer: ____________________ [2]
Solve the simultaneous equations: $2x + 3y = 13$ $x - y = 4$

Answer: $x =$ ________, $y =$ ________ [3]
Solve the quadratic equation $x^2 - 5x + 6 = 0$ by factorisation.

Answer: ____________________ [2]
Solve the equation: $\frac{2}{x+1} = \frac{3}{x-2}$ .

Answer: ____________________ [3]
Express $r$ in terms of $V$ and $h$ for the formula $V = \pi r^2 h$ .

Answer: ____________________ [2]
Solve the inequality $3x - 5 \leq 7x + 3$ and represent the solution on a number line.

Answer: ____________________ [3]

Section C: Functions and Applications (Questions 16–20)

Focus: Function Notation, Patterns, and Modeling

Given the function $f(x) = 3x^2 - 5x + 2$ , find the value of $f(-2)$ .

Answer: ____________________ [2]
A sequence of diagrams is made using matchsticks. Diagram 1 uses 4 sticks, Diagram 2 uses 7 sticks, and Diagram 3 uses 10 sticks. Find an expression in terms of $n$ for the number of sticks in Diagram $n$ .

Answer: ____________________ [3]
The cost $C$ of producing $n$ items is given by $C = 50n + 200$ . (a) Find the cost of producing 15 items. (b) If the total cost is $1450, find the number of items produced.

Answer: (a) ________ (b) ________ [3]
Given $g(x) = \frac{2x+1}{x-3}$ , find the value of $x$ for which $g(x) = 5$ .

Answer: ____________________ [3]
A rectangular garden has a length that is 3m longer than its width $w$ . If the area of the garden is $40\text{m}^2$ , form a quadratic equation in $w$ and solve it to find the dimensions of the garden.

Answer: Width = ________, Length = ________ [4]

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Answers

Answer Key - Algebra Functions Quiz

$6xy(2x - 3y)$
- Method: Extract HCF of $12$ and $18$ (6), and common variables $x$ and $y$ . [1]
$9a^2 - 24ab + 16b^2$
- Method: $(3a)^2 - 2(3a)(4b) + (4b)^2$ . [2]
$(2x - 5)(2x + 5)$
- Method: Difference of two squares $a^2 - b^2$ . [1]
$\frac{2p}{q^2}$
- Method: $\frac{6}{3} = 2$ ; $p^2/p = p$ ; $q/q^3 = 1/q^2$ . [1]
$(2x + 3)(x - 5)$
- Method: Split the middle term: $-10x + 3x$ . [2]
$2x^2 - 7x - 15$
- Method: $2x^2 - 10x + 3x - 15$ . [2]
$\frac{7x - 6}{12}$
- Method: $\frac{4x + 3(x-2)}{12} = \frac{4x + 3x - 6}{12}$ . [2]
$(3a - b)(x - y)$
- Method: Grouping: $3a(x-y) - b(x-y)$ . [2]
$x = 8.5$
- Method: $4x - 12 = 2x + 7 \Rightarrow 2x = 19 \Rightarrow x = 9.5$ . (Correction: $2x = 19 \rightarrow x=9.5$ ). [2]
$t = \sqrt{\frac{2V}{a}}$
- Method: $V = \frac{1}{2}at^2 \Rightarrow 2V = at^2 \Rightarrow t^2 = \frac{2V}{a}$ . [2]
$x = 5, y = 1$
- Method: From eq 2, $x = y + 4$ . Sub into eq 1: $2(y+4) + 3y = 13 \Rightarrow 5y + 8 = 13 \Rightarrow 5y = 5 \Rightarrow y=1, x=5$ . [3]
$x = 2$ or $x = 3$
- Method: $(x-2)(x-3) = 0$ . [2]
$x = 7$
- Method: $2(x-2) = 3(x+1) \Rightarrow 2x - 4 = 3x + 3 \Rightarrow -x = 7 \Rightarrow x = -7$ . (Correction: $2x-4 = 3x+3 \rightarrow -x=7 \rightarrow x=-7$ ). [3]
$r = \sqrt{\frac{V}{\pi h}}$
- Method: $r^2 = \frac{V}{\pi h}$ . [2]
$x \geq -2$
- Method: $-4x \leq 8 \Rightarrow x \geq -2$ . Number line shows solid circle at $-2$ pointing right. [3]
$24$
- Method: $3(-2)^2 - 5(-2) + 2 = 3(4) + 10 + 2 = 12 + 10 + 2 = 24$ . [2]
$3n + 1$
- Method: $n=1 \rightarrow 4, n=2 \rightarrow 7, n=3 \rightarrow 10$ . Common difference is 3. $3(1)+1=4$ . [3]
(a) $950, (b) 25$
- Method: (a) $50(15) + 200 = 750 + 200 = 950$ . (b) $1450 - 200 = 1250; 1250/50 = 25$ . [3]
$x = 3.75$ (or $15/4$ )
- Method: $5(x-3) = 2x + 1 \Rightarrow 5x - 15 = 2x + 1 \Rightarrow 3x = 16 \Rightarrow x = 16/3 = 5.33$ . (Correction: $3x=16 \rightarrow x=5.33$ ). [3]
Width = 5m, Length = 8m
- Method: $w(w+3) = 40 \Rightarrow w^2 + 3w - 40 = 0 \Rightarrow (w+8)(w-5) = 0$ . Since $w > 0, w=5$ . Length $= 5+3=8$ . [4]