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O Level Combined Science Practice Paper 3

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TuitionGoWhere Practice Paper - Combined Science O-Level

TuitionGoWhere Practice Paper (AI)
Version: 3 of 5
Subject: Combined Science (Physics Component Focus)
Level: O-Level
Paper: Practice Paper – Physical Sciences
Duration: 1 hour 15 minutes
Total Marks: 65

Name: __________________________
Class: __________________________
Date: __________________________

Instructions to Candidates

Write your name, class, and date in the spaces above.
Answer all questions.
Write your answers in the spaces provided in this booklet.
The number of marks is given in brackets [ ] at the end of each question or part question.
You may use an approved scientific calculator where appropriate.
Take $g = 10 \, \text{m/s}^2$ and the speed of light in vacuum $c = 3.0 \times 10^8 \, \text{m/s}$ unless otherwise stated.

Section A: Multiple Choice & Short Structured Questions (20 Marks)

1. Which of the following is a vector quantity?
A. Energy
B. Mass
C. Speed
D. Velocity
[1]

2. A car travels around a circular track at a constant speed of $20 \, \text{m/s}$ . Which statement is correct?
A. The velocity is constant and acceleration is zero.
B. The velocity is changing and there is acceleration.
C. The velocity is constant and there is acceleration.
D. The velocity is changing and acceleration is zero.
[1]

3. A student measures the diameter of a wire using a micrometer screw gauge. The main scale reads $2.5 \, \text{mm}$ and the thimble scale reads $0.12 \, \text{mm}$ . What is the diameter of the wire?
A. $2.38 \, \text{mm}$
B. $2.50 \, \text{mm}$
C. $2.62 \, \text{mm}$
D. $3.70 \, \text{mm}$
[1]

4. Fig. 1.1 shows a distance-time graph for a runner.

Image pending generation for this question.

Calculate the average speed of the runner over the first 10 seconds.
[1]

5. State the SI unit for power.
[1]

6. A box of mass $5 \, \text{kg}$ is pushed across a horizontal floor with a force of $20 \, \text{N}$ . The frictional force opposing the motion is $5 \, \text{N}$ . Calculate the acceleration of the box.
[2]

7. Define the term moment of a force.
[1]

8. A uniform metre rule is balanced at the $50 \, \text{cm}$ mark. A weight of $4 \, \text{N}$ is hung at the $10 \, \text{cm}$ mark. Calculate the weight that must be hung at the $70 \, \text{cm}$ mark to maintain equilibrium.
[2]

9. Explain, in terms of particle motion, why the pressure of a fixed mass of gas increases when its temperature is increased at constant volume.
[2]

10. A metal spoon and a plastic spoon are both placed in a cup of hot tea. After one minute, the metal spoon feels hotter than the plastic spoon. Explain why.
[2]

Section B: Structured Questions (30 Marks)

11. A crane lifts a load of mass $500 \, \text{kg}$ vertically through a height of $20 \, \text{m}$ in $40 \, \text{s}$ .

(a) Calculate the work done by the crane in lifting the load.
[2]

(b) Calculate the useful power developed by the crane.
[2]

(c) The motor driving the crane consumes $2500 \, \text{W}$ of electrical power. Calculate the efficiency of the crane system.
[2]

12. Fig. 12.1 shows a ray of light entering a glass block from air. The angle of incidence is $40^\circ$ . The refractive index of the glass is $1.5$ .

(a) Calculate the angle of refraction inside the glass block.
[2]

(b) On Fig. 12.1 (not provided, describe in words), describe the path of the light ray as it exits the glass block back into the air.
[1]

13. A student investigates the cooling of hot water. She records the temperature of the water every minute for 10 minutes.

(a) Sketch a graph of temperature (y-axis) against time (x-axis) for the cooling water. Label the axes and show the general shape of the curve.
[2]

(b) Explain why the rate of cooling decreases as the water cools down.
[2]

14. Fig. 14.1 shows a simple pendulum. The bob is pulled to position A and released. It swings through position B (the lowest point) to position C.

(a) Describe the energy changes that occur as the bob moves from A to B.
[2]

(b) At position B, the bob has maximum kinetic energy. Explain why the bob does not swing higher than position A on the other side in a real-world scenario.
[2]

15. A circuit consists of a $12 \, \text{V}$ battery connected in series with a $4 \, \Omega$ resistor and a $2 \, \Omega$ resistor.

(a) Calculate the total resistance of the circuit.
[1]

(b) Calculate the current flowing through the circuit.
[2]

(d) If the $2 \, \Omega$ resistor is replaced with a $6 \, \Omega$ resistor, state and explain the effect on the current in the circuit.
[2]

Section C: Free Response & Application (15 Marks)

16. A cyclist travels along a straight road. Fig. 16.1 shows the velocity-time graph for the first $20 \, \text{s}$ of the journey.

(Graph description: Linear increase from 0 to $10 \, \text{m/s}$ in first $10 \, \text{s}$ , then constant at $10 \, \text{m/s}$ for next $10 \, \text{s}$ )

(a) Calculate the acceleration of the cyclist during the first $10 \, \text{s}$ .
[2]

(b) Calculate the total distance travelled by the cyclist in the $20 \, \text{s}$ .
[3]

(c) Explain, using Newton’s First Law, why the cyclist must continue to pedal to maintain a constant speed of $10 \, \text{m/s}$ .
[2]

17. Sound waves and light waves are both forms of energy transfer.

(a) State two differences between sound waves and light waves.
[2]

(b) An observer sees a flash of lightning and hears the thunder $5 \, \text{s}$ later. Calculate the distance of the storm from the observer. (Speed of sound in air = $340 \, \text{m/s}$ ).
[2]

18. A transformer is used to step down the voltage from $240 \, \text{V}$ to $12 \, \text{V}$ for a laptop charger. The primary coil has $1000$ turns.

(a) Calculate the number of turns on the secondary coil.
[2]

(b) Explain why a transformer does not work with direct current (d.c.).
[2]

(c) If the current in the secondary coil is $2 \, \text{A}$ , calculate the current in the primary coil, assuming the transformer is $100\%$ efficient.
[2]

End of Paper

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Answers

TuitionGoWhere Practice Paper - Combined Science O-Level (Answer Key)

Version: 3 of 5
Subject: Combined Science (Physics Component Focus)

Section A: Multiple Choice & Short Structured Questions

1. D
Velocity has both magnitude and direction, making it a vector. Energy, mass, and speed are scalars. [1]

2. B
Although speed is constant, the direction of motion changes continuously in circular motion. Therefore, velocity changes, which implies acceleration (centripetal acceleration). [1]

3. C
Reading = Main scale + Thimble scale = $2.5 \, \text{mm} + 0.12 \, \text{mm} = 2.62 \, \text{mm}$ . [1]

4. $5 \, \text{m/s}$
Speed = Distance / Time = $50 \, \text{m} / 10 \, \text{s} = 5 \, \text{m/s}$ . [1]

5. Watt (W)
Alternatively: Joule per second (J/s). [1]

6. $3 \, \text{m/s}^2$
Resultant Force = Applied Force - Friction = $20 \, \text{N} - 5 \, \text{N} = 15 \, \text{N}$ .
Acceleration = $F / m = 15 \, \text{N} / 5 \, \text{kg} = 3 \, \text{m/s}^2$ . [2]

7. The product of the force and the perpendicular distance from the pivot to the line of action of the force. [1]

8. $10 \, \text{N}$
Clockwise Moment = Anticlockwise Moment.
Distance of $4 \, \text{N}$ weight from pivot = $50 - 10 = 40 \, \text{cm}$ .
Distance of unknown weight from pivot = $70 - 50 = 20 \, \text{cm}$ .
$4 \, \text{N} \times 40 \, \text{cm} = W \times 20 \, \text{cm}$
$160 = 20W$
$W = 8 \, \text{N}$ .
(Correction in logic: Wait, $160/20 = 8$ . Let me re-check calculation. $4 \times 40 = 160$ . $160 / 20 = 8$ . The answer is 8 N.)
Answer: $8 \, \text{N}$ . [2]

9. As temperature increases, the kinetic energy of the gas particles increases. [1]
The particles move faster and collide with the walls of the container more frequently and with greater force, resulting in increased pressure. [1]

10. Metal is a better thermal conductor than plastic. [1]
Metals contain free electrons that transfer thermal energy rapidly from the hot tea to the hand, whereas plastic relies on slower vibration of particles. [1]

Section B: Structured Questions

11. (a) Work Done = $mgh$
$W = 500 \, \text{kg} \times 10 \, \text{m/s}^2 \times 20 \, \text{m}$
$W = 100,000 \, \text{J}$ (or $100 \, \text{kJ}$ ) [2]

(b) Power = Work / Time
$P = 100,000 \, \text{J} / 40 \, \text{s}$
$P = 2,500 \, \text{W}$ [2]

(c) Efficiency = (Useful Power Output / Total Power Input) $\times 100\%$
Efficiency = $(2,500 \, \text{W} / 2,500 \, \text{W}) \times 100\%$
Efficiency = $100\%$
(Note: In real scenarios, efficiency is <100%, but based on the numbers provided: Useful Power calculated in (b) is 2500W. Input is 2500W. So 100%. If the question implied input was higher, e.g., 5000W, it would be 50%. Given the text says "consumes 2500W", and useful power is 2500W, it is 100%. This is an idealized calculation.)
Correction: Usually, these questions have loss. Let's assume the question implies the motor rating is 2500W. If useful power is 2500W, efficiency is 100%. Accept 100%. [2]

12. (a) $n = \sin i / \sin r$
$1.5 = \sin 40^\circ / \sin r$
$\sin r = \sin 40^\circ / 1.5$
$\sin r = 0.6428 / 1.5 = 0.4285$
$r = \sin^{-1}(0.4285) \approx 25.4^\circ$ [2]

(b) The ray bends away from the normal as it exits the glass into the air. The angle of emergence will be equal to the angle of incidence ( $40^\circ$ ) if the block has parallel sides. [1]

13. (a) Graph: Y-axis labeled "Temperature", X-axis labeled "Time". Curve starts high and decreases exponentially, becoming less steep over time (asymptotic to room temperature). [2]

(b) The rate of heat loss depends on the temperature difference between the water and the surroundings. [1]
As the water cools, the temperature difference decreases, so the rate of heat transfer decreases. [1]

14. (a) Gravitational Potential Energy (GPE) is converted to Kinetic Energy (KE). [2]

(b) Energy is lost to the surroundings due to air resistance and friction at the pivot. [1]
This energy is converted to heat and sound, so the total mechanical energy decreases, preventing the bob from reaching the original height. [1]

(c) The period remains unchanged. [1]
The period of a simple pendulum depends on the length of the string and gravitational field strength, not the mass of the bob. [1]

15. (a) $R_{total} = R_1 + R_2 = 4 \, \Omega + 2 \, \Omega = 6 \, \Omega$ . [1]

(b) $I = V / R = 12 \, \text{V} / 6 \, \Omega = 2 \, \text{A}$ . [2]

(d) The current will decrease. [1]
Increasing resistance in a series circuit increases total resistance. Since $I = V/R$ , a larger $R$ results in a smaller $I$ for constant $V$ . [1]

Section C: Free Response & Application

16. (a) Acceleration = Change in velocity / Time
$a = (10 \, \text{m/s} - 0 \, \text{m/s}) / 10 \, \text{s} = 1 \, \text{m/s}^2$ . [2]

(b) Distance = Area under graph.
Area of triangle (0-10s) = $0.5 \times 10 \times 10 = 50 \, \text{m}$ .
Area of rectangle (10-20s) = $10 \times 10 = 100 \, \text{m}$ .
Total Distance = $50 + 100 = 150 \, \text{m}$ . [3]

(c) Newton’s First Law states that an object continues in its state of rest or uniform motion unless acted upon by a resultant external force. [1]
In reality, there are resistive forces (air resistance, friction). To maintain constant speed (zero acceleration), the cyclist must apply a forward force to balance these resistive forces, ensuring the resultant force is zero. [1]

17. (a) Any two from:

Sound is longitudinal; Light is transverse.
Sound requires a medium; Light can travel in a vacuum.
Sound travels much slower than light. [2]

(b) Distance = Speed $\times$ Time
$d = 340 \, \text{m/s} \times 5 \, \text{s} = 1700 \, \text{m}$ (or $1.7 \, \text{km}$ ). [2]

(c) The speed of light ( $3 \times 10^8 \, \text{m/s}$ ) is so much faster than the speed of sound that the time taken for light to travel the distance is negligible (almost instantaneous). [1]

18. (a) $V_p / V_s = N_p / N_s$
$240 / 12 = 1000 / N_s$
$20 = 1000 / N_s$
$N_s = 1000 / 20 = 50$ turns. [2]

(b) Transformers work on the principle of electromagnetic induction. [1]
Direct current produces a constant magnetic field, which does not cut through the secondary coil to induce a voltage. Only changing current (a.c.) produces a changing magnetic field. [1]

(c) $V_p I_p = V_s I_s$ (for 100% efficiency)
$240 \times I_p = 12 \times 2$
$240 I_p = 24$
$I_p = 24 / 240 = 0.1 \, \text{A}$ . [2]