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O Level Chemistry Redox Electrochemistry Quiz

Free O Level Chemistry Redox Electrochemistry quiz, Qwen3.6 AI version, with questions, answers, and O Level-style practice for Singapore students.

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O Level Chemistry AI Generated Generated by Qwen3.6 Plus Updated 2026-08-17

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Answers

O-Level Chemistry Quiz - Redox Electrochemistry (Answer Key)

1. B
Loss of electrons is oxidation (OIL RIG). [1]

2. A
Zn loses electrons to form Zn2+Zn^{2+}. The species that loses electrons is the reducing agent. [1]

3. +6
Let Cr be xx. 2x+7(2)=22x14=22x=12x=+62x + 7(-2) = -2 \Rightarrow 2x - 14 = -2 \Rightarrow 2x = 12 \Rightarrow x = +6. [1]

4. Reddish-brown vapour / Brown gas
Bromide ions (BrBr^-) are oxidised to bromine (Br2Br_2) at the anode. [1]

5. Hydrogen ion (H+H^+)
In dilute aqueous solutions, H+H^+ is preferentially discharged over Na+Na^+ because hydrogen is lower in the reactivity series. [1]

6.
(a) Cu2+(aq)+2eCu(s)Cu^{2+}(aq) + 2e^- \rightarrow Cu(s) [1]
(b) Copper(II) ions (Cu2+Cu^{2+}) are removed from the solution to form copper metal at the cathode. As the concentration of blue Cu2+Cu^{2+} ions decreases, the colour fades. [2]

7.
(a) The copper anode decreases in size / dissolves. [1]
(b) Cu(s)Cu2+(aq)+2eCu(s) \rightarrow Cu^{2+}(aq) + 2e^- [1]
(c) For every Cu2+Cu^{2+} ion discharged at the cathode, one Cu atom from the anode dissolves to form a Cu2+Cu^{2+} ion. The rate of removal equals the rate of formation, so concentration stays constant. [2]

8.
(a) Chlorine gas (Cl2Cl_2). [1]
(b) Although OHOH^- is lower in the electrochemical series than ClCl^-, the concentration of ClCl^- ions is much higher in concentrated solution. Therefore, ClCl^- is preferentially discharged. [2]

9.
(a) 2 : 1 [1]
(b) 4OH(aq)O2(g)+2H2O(l)+4e4OH^-(aq) \rightarrow O_2(g) + 2H_2O(l) + 4e^-
OR 2H2O(l)O2(g)+4H+(aq)+4e2H_2O(l) \rightarrow O_2(g) + 4H^+(aq) + 4e^- [2]

10.
(a) Silver (AgAg). [1]
(b) Silver is lower in the reactivity series than hydrogen. Therefore, Ag+Ag^+ ions are preferentially discharged over H+H^+ ions at the cathode. [2]

11.
(a) The colourless solution turns brown / dark brown. [1]
(b) Cl2+2I2Cl+I2Cl_2 + 2I^- \rightarrow 2Cl^- + I_2 [2]
(c) Chlorine (Cl2Cl_2). [1]

12.
(a) From purple to colourless. [1]
(b) Iron(II) ions (Fe2+Fe^{2+}) lose electrons to form Iron(III) ions (Fe3+Fe^{3+}). Loss of electrons is oxidation. The MnO4MnO_4^- accepts these electrons and is reduced. [2]

13.
(a) -3 [x+4(+1)=+1x=3x + 4(+1) = +1 \Rightarrow x = -3] [1]
(b) +7 [1+x+4(2)=0x=+71 + x + 4(-2) = 0 \Rightarrow x = +7] [1]
(c) +6 [x+3(2)=0x=+6x + 3(-2) = 0 \Rightarrow x = +6] [1]

14.
(a) Fe changes from +2 in Fe2+Fe^{2+} to +3 in Fe3+Fe^{3+}. Increase in oxidation state is oxidation. [1]
(b) O changes from -1 in H2O2H_2O_2 to -2 in H2OH_2O. Decrease in oxidation state is reduction. [2]

15.
(a) Magnesium (MgMg). [1]
(b) Hydrogen changes from +1 in HClHCl to 0 in H2H_2. The decrease in oxidation state indicates reduction. Since reduction occurs, it is a redox reaction. [2]

16.
(a) Magnesium. [1]
(b) Magnesium is more reactive than copper. It has a greater tendency to lose electrons and form ions, making it the negative electrode (source of electrons). [2]

17.
(a) 2H+(aq)+2eH2(g)2H^+(aq) + 2e^- \rightarrow H_2(g) [2]
(b) From Magnesium to Copper. [1]

18.
(a) 2H2+O22H2O2H_2 + O_2 \rightarrow 2H_2O [1]
(b) The only product is water (non-polluting) / No carbon dioxide produced / High efficiency. [1]
(c) Hydrogen is difficult/expensive to store / Lack of refuelling infrastructure / Hydrogen is flammable/explosive. [1]

19.
(a) Zinc (or Magnesium). [1]
(b) Zinc is more reactive than iron. Zinc loses electrons more easily than iron. The zinc oxidises (corrodes) in preference to the iron. Electrons flow from zinc to iron, preventing the iron from losing electrons and rusting. [3]

20.
(a) Cathode. [1]
(b) Silver nitrate solution (AgNO3(aq)AgNO_3(aq)) / Any soluble silver salt. [1]
(c) Ag+(aq)+eAg(s)Ag^+(aq) + e^- \rightarrow Ag(s) [2]