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O Level Chemistry Periodic Table Quiz

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O Level Chemistry AI Generated Generated by DeepSeek V4 Pro Updated 2026-08-17

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O-Level Chemistry Quiz - Periodic Table: Answer Key and Marking Scheme

Total Marks: 40


Section A: Multiple Choice (5 × 1 mark = 5 marks)

QuestionAnswerExplanation
1CThe modern Periodic Table arranges elements in order of increasing proton (atomic) number. Earlier versions used relative atomic mass, but this led to anomalies (e.g., argon and potassium).
2BElectronic configuration 2,8,2 indicates 3 occupied electron shells (Period 3) and 2 valence electrons (Group II).
3CMetallic character decreases across Period 3 as elements change from metals (Na, Mg, Al) to metalloid (Si) to non-metals (P, S, Cl). Electronegativity and ionisation energy generally increase across the period.
4BXCl₂ and XO indicate element X has a valency of 2, forming X²⁺ ions. Elements in Group II typically form 2+ ions.
5BLithium and potassium are both in Group I (alkali metals) and have the same number of valence electrons (1), giving them very similar chemical properties.

Section B: Short Answer (5 × 3 marks = 15 marks)

Question 6

(a) Explain the trend in atomic radius across Period 3. [2 marks]

Answer: Across Period 3, the atomic radius decreases from sodium to chlorine. [1 mark] This is because the number of protons in the nucleus increases, so the nuclear charge increases. The electrons are added to the same outer shell, so the shielding effect remains approximately the same. The increased nuclear attraction pulls the outer electrons closer to the nucleus, decreasing the atomic radius. [1 mark]

Marking notes:

  • Award 1 mark for stating the trend (decreases).
  • Award 1 mark for explanation linking increased nuclear charge with same shell/shielding and stronger attraction.

(b) Explain why silicon has a much higher melting point than sodium. [1 mark]

Answer: Silicon has a giant covalent structure with strong covalent bonds between silicon atoms throughout the lattice, requiring a large amount of energy to break. [1/2 mark] Sodium has a giant metallic structure with metallic bonding; although strong, the covalent bonds in silicon are stronger and more extensive than the metallic bonds in sodium. [1/2 mark]

Marking notes:

  • Award 1 mark for identifying silicon's giant covalent structure and linking to strong covalent bonds.
  • Accept reference to the difference in bonding type and relative bond strengths.

Question 7

(a) Write a balanced chemical equation, with state symbols, for the reaction of element Y with water. [2 marks]

Answer: 2Y(s) + 2H₂O(l) → 2YOH(aq) + H₂(g)
OR if Y is identified as a specific Group I metal:
2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)
2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g)

Marking notes:

  • Award 1 mark for correct formulae of reactants and products.
  • Award 1 mark for correct balancing and state symbols.
  • Accept any Group I metal (Li, Na, K, Rb, Cs) as Y.

(b) State one safety precaution that should be taken when carrying out this reaction and explain why it is necessary. [1 mark]

Answer: Use a safety screen / wear safety goggles / use a small piece of metal / use tongs to handle the metal. [1/2 mark] The reaction is very vigorous/exothermic and the metal may spit or the hydrogen gas produced may ignite, causing injury. [1/2 mark]

Marking notes:

  • Award 1/2 mark for a valid precaution.
  • Award 1/2 mark for a valid explanation linked to the vigorous nature of the reaction.

Question 8

(a) Identify element Z and state its Group and Period in the Periodic Table. [2 marks]

Answer: Element Z is chlorine (Cl). [1 mark] It is in Group VII (or Group 17), Period 3. [1 mark]

Marking notes:

  • Electronic configuration 2,8,7 indicates 17 electrons, so the element is chlorine.
  • 3 shells = Period 3; 7 valence electrons = Group VII/17.

(b) Predict the formula of the compound formed between element Z and calcium. [1 mark]

Answer: CaCl₂

Marking notes:

  • Calcium (Group II) forms Ca²⁺ ions; chlorine (Group VII) forms Cl⁻ ions.
  • The compound must be electrically neutral: one Ca²⁺ requires two Cl⁻ ions.

Question 9

(a) Explain why chlorine reacts with potassium bromide solution but bromine does not react with potassium chloride solution. [2 marks]

Answer: Chlorine is more reactive than bromine (chlorine is above bromine in Group VII). [1 mark] A more reactive halogen can displace a less reactive halogen from its halide solution. Therefore, chlorine displaces bromine from potassium bromide solution. Bromine is less reactive than chlorine, so it cannot displace chlorine from potassium chloride solution. [1 mark]

Marking notes:

  • Award 1 mark for stating the relative reactivity.
  • Award 1 mark for explaining the displacement principle.

(b) Write an ionic equation for the reaction between chlorine and potassium iodide solution. [1 mark]

Answer: Cl₂(aq) + 2I⁻(aq) → 2Cl⁻(aq) + I₂(aq)

Marking notes:

  • Award 1 mark for correct ionic equation with correct charges and state symbols.
  • Accept: Cl₂ + 2I⁻ → 2Cl⁻ + I₂ (state symbols not essential for the mark if the rest is correct).

Question 10

State three characteristic properties of transition elements that are not typical of Group I metals. [3 marks]

Answer (any three, 1 mark each):

  1. Transition elements have high melting points / high densities (Group I metals have low melting points and low densities).
  2. Transition elements form coloured compounds (Group I compounds are usually white/colourless).
  3. Transition elements have variable oxidation states (Group I metals have only +1 oxidation state).
  4. Transition elements and their compounds act as catalysts (Group I metals are not typically used as catalysts).
  5. Transition elements are harder and stronger (Group I metals are soft).

Marking notes:

  • Award 1 mark for each correct property that contrasts with Group I metals.
  • The property must be clearly stated and must be characteristic of transition elements.

Section C: Structured Questions (5 × 2 marks = 10 marks)

Question 11

(a) Write the electronic configuration of element A. [1 mark]

Answer: 2,8,8,2

Marking notes:

  • Group II = 2 valence electrons; Period 4 = 4 occupied shells.
  • Calcium (Ca) is the actual element: 20 electrons arranged as 2,8,8,2.

(b) Predict whether the atomic radius of element A is larger or smaller than that of magnesium (Group II, Period 3). Explain your answer. [1 mark]

Answer: The atomic radius of element A is larger than that of magnesium. [1/2 mark] Element A has one more occupied electron shell than magnesium (4 shells vs. 3 shells). The outer electrons are further from the nucleus, and the increased shielding effect from the additional inner shells outweighs the increased nuclear charge, resulting in a larger atomic radius. [1/2 mark]

Marking notes:

  • Award 1/2 mark for correct prediction (larger).
  • Award 1/2 mark for explanation referencing additional electron shell and increased shielding.

Question 12

Write a balanced chemical equation for this reaction and state one physical property of the oxide formed. [2 marks]

Answer: 2A(s) + O₂(g) → 2AO(s) OR 2Ca(s) + O₂(g) → 2CaO(s) [1 mark]
Physical property: The oxide is a white solid with a high melting point / basic oxide / ionic compound. [1 mark]

Marking notes:

  • Award 1 mark for correct balanced equation (accept A or Ca).
  • Award 1 mark for any valid physical property of a Group II oxide.

Question 13

(a) State the physical state and colour of element B at room temperature and pressure. [1 mark]

Answer: Element B (chlorine) is a greenish-yellow gas at room temperature and pressure.

Marking notes:

  • Award 1 mark for both correct state (gas) and colour (greenish-yellow/yellow-green).

(b) Describe and explain the trend in reactivity of the Group VII elements down the group. [1 mark]

Answer: Reactivity decreases down the group. [1/2 mark] This is because the atomic radius increases and the shielding effect increases, so the attraction for an incoming electron decreases, making it harder to gain an electron. [1/2 mark]

Marking notes:

  • Award 1/2 mark for stating the trend (decreases).
  • Award 1/2 mark for explanation linking increased atomic radius/shielding to decreased ability to gain electrons.

Question 14

State the type of bonding present in this compound and draw a dot-and-cross diagram to show its bonding. [2 marks]

Answer: Covalent bonding. [1 mark]
Dot-and-cross diagram showing H and Cl sharing one pair of electrons, with Cl having three lone pairs and H having no lone pairs. [1 mark]

Marking notes:

  • Award 1 mark for identifying covalent bonding.
  • Award 1 mark for a correct dot-and-cross diagram of HCl showing shared pair and correct outer shells.

Question 15

(a) Write a balanced chemical equation, with state symbols, for the reaction that occurs. [1 mark]

Answer: 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g)

Marking notes:

  • Award 1 mark for correct balanced equation with state symbols.

(b) Name the gas produced and describe a test to identify this gas. [1 mark]

Answer: Hydrogen gas. [1/2 mark] Test: Place a lighted splint near the mouth of the test tube; hydrogen burns with a 'pop' sound. [1/2 mark]

Marking notes:

  • Award 1/2 mark for naming hydrogen.
  • Award 1/2 mark for describing the test with the expected observation.

Section D: Data Analysis and Application (5 × 2 marks = 10 marks)

Question 16

Explain why potassium is more reactive than sodium, with reference to their atomic structure. [2 marks]

Answer: Potassium has a larger atomic radius than sodium because it has one more occupied electron shell. [1 mark] The outer electron in potassium is further from the nucleus and experiences greater shielding from inner electrons, so it is less strongly attracted to the nucleus and is more easily lost, making potassium more reactive. [1 mark]

Marking notes:

  • Award 1 mark for reference to larger atomic radius/more shells.
  • Award 1 mark for linking weaker attraction of outer electron to easier loss/higher reactivity.

Question 17

(a) State the position of copper in the reactivity series relative to hydrogen. [1 mark]

Answer: Copper is below hydrogen in the reactivity series.

Marking notes:

  • Award 1 mark for stating copper is below/less reactive than hydrogen.

(b) Write a balanced chemical equation for this reaction. [1 mark]

Answer: 2CuO(s) + C(s) → 2Cu(s) + CO₂(g)

Marking notes:

  • Award 1 mark for correct balanced equation with correct formulae.

Question 18

State two uses of copper that depend on its physical properties, and identify the property that makes it suitable for each use. [2 marks]

Answer (any two valid uses with corresponding properties, 1 mark each):

  1. Use: Electrical wiring → Property: Excellent electrical conductivity / ductile.
  2. Use: Water pipes / plumbing → Property: Malleable / resistant to corrosion / durable.
  3. Use: Cooking utensils → Property: Excellent thermal conductivity.

Marking notes:

  • Award 1 mark for each correct use with a correctly linked physical property.

Question 19

Explain why silicon has the highest melting point among these elements. [2 marks]

Answer: Silicon has a giant covalent structure. [1 mark] A large amount of energy is required to break the many strong covalent bonds between silicon atoms throughout the lattice, resulting in a very high melting point. The other elements have metallic bonding (Na, Mg, Al) or simple molecular structures (P, S, Cl) with weaker intermolecular forces. [1 mark]

Marking notes:

  • Award 1 mark for identifying giant covalent structure.
  • Award 1 mark for linking strong covalent bonds to high energy requirement and comparing with bonding in other elements.

Question 20

(a) Predict the Group of element Q in the Periodic Table. [1 mark]

Answer: Group I

Marking notes:

  • Formula Q₂O indicates Q has a valency of 1, forming Q⁺ ions. Group I elements form 1+ ions.

(b) Suggest one safety precaution needed when handling element Q and explain why. [1 mark]

Answer: Handle with tongs / use a safety screen / wear gloves. [1/2 mark] Element Q is a Group I metal and reacts vigorously/explosively with moisture on skin or in air, causing burns. [1/2 mark]

Marking notes:

  • Award 1/2 mark for a valid precaution.
  • Award 1/2 mark for a valid explanation linked to the high reactivity of Group I metals.

END OF ANSWER KEY