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O Level Biology Plant Biology Quiz

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O Level Biology From Real Exams Generated by Qwen3.6 Plus Updated 2026-06-03

Questions

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O-Level Biology Quiz - Plant Biology

Name: ________________________
Class: ________________________
Date: ________________________
Score: ______ / 40

Duration: 45 minutes
Total Marks: 40

Instructions:

  1. Answer all questions.
  2. Write your answers in the spaces provided.
  3. The number of marks is indicated in brackets [ ] at the end of each question or part question.
  4. Diagrams are not drawn to scale unless stated.

Section A: Structured Questions (20 marks)

1. Name the process by which plants lose water vapour from the leaves to the atmosphere. [1]


2. State the chemical equation for photosynthesis, using either words or chemical symbols. [2]



3. Fig. 3.1 shows a cross-section of a leaf.

(Imagine a diagram showing the upper epidermis, palisade mesophyll, spongy mesophyll, lower epidermis, and a stoma with guard cells.)

(a) Identify the tissue labelled P if it consists of tightly packed cells containing many chloroplasts. [1]


(b) Explain one structural adaptation of the cells in tissue P that maximises the rate of photosynthesis. [2]



4. A student investigated the effect of light intensity on the rate of photosynthesis of an aquatic plant. The student counted the number of bubbles produced in one minute at different distances from a lamp.

(a) Explain why the number of bubbles is a valid measure of the rate of photosynthesis. [1]


(b) As the lamp was moved further away, the number of bubbles decreased. Explain this result in terms of limiting factors. [2]



5. Describe the route taken by a pollen tube from the moment it lands on the stigma until fertilisation occurs. [3]




6. Mineral ions, such as nitrate and magnesium, are absorbed by root hair cells from the soil.

(a) Name the process by which mineral ions are absorbed when their concentration in the soil is lower than in the root hair cell. [1]


(b) Explain why this process requires energy. [2]



7. Fig. 7.1 shows a potometer used to measure the rate of water uptake by a leafy shoot.

(Imagine a diagram of a potometer with a capillary tube, air bubble, reservoir, and leafy shoot.)

(a) State the relationship between water uptake and transpiration. [1]


(b) Suggest why the rate of water uptake might not be exactly equal to the rate of transpiration. [1]


8. Sucrose is produced in the leaves of a plant.

(a) Name the tissue responsible for transporting sucrose to other parts of the plant. [1]


(b) Name the process of transporting sucrose. [1]


9. Compare the structure of a xylem vessel and a phloem sieve tube element. State one difference. [1]


10. Explain why wilting occurs in plants on a hot, dry day. [2]




Section B: Data Interpretation & Application (20 marks)

11. Fig. 11.1 shows the effect of carbon dioxide concentration on the rate of photosynthesis at two different temperatures, 15°C and 25°C.

(Imagine a graph: X-axis = CO2 concentration (%), Y-axis = Rate of Photosynthesis. Two curves: Curve A (15°C) plateaus early at a lower rate. Curve B (25°C) rises higher and plateaus later.)

(a) Describe the effect of increasing carbon dioxide concentration on the rate of photosynthesis at 25°C, up to the point of saturation. [2]



(b) Explain why the rate of photosynthesis at 25°C is higher than at 15°C when carbon dioxide concentration is high. [2]



(c) Identify the limiting factor for photosynthesis at point X on the 25°C curve, where the line has become horizontal. [1]


12. A farmer grows crops in a greenhouse. He adds carbon dioxide to the air inside the greenhouse.

(a) Explain how adding carbon dioxide can increase the yield of the crop. [2]



(b) Suggest one other factor the farmer should control to ensure the added carbon dioxide is effective. [1]


13. Fig. 13.1 shows the distribution of stomata on the upper and lower surfaces of two different leaves, Leaf A and Leaf B.

LeafUpper Surface (stomata/mm²)Lower Surface (stomata/mm²)
A0250
B100100

Leaf A is from a plant growing in a sunny, dry environment. Leaf B is from a plant floating on water (hydrophyte).

(a) Explain why Leaf A has no stomata on its upper surface. [2]



(b) Explain why Leaf B has stomata on its upper surface. [2]



14. An experiment was conducted to investigate the effect of wind speed on the rate of transpiration. An electric fan was placed at different distances from a leafy shoot in a potometer.

Distance of Fan (cm)Time for bubble to move 10 cm (s)
10050
5030
2015
1010

(a) Calculate the rate of water uptake (cm/s) when the fan is 50 cm away. Show your working. [2]

<br> <br>

Rate = _______________ cm/s

(b) Explain the effect of increasing wind speed on the rate of transpiration. [3]




15. Plants require magnesium ions for healthy growth.

(a) State the function of magnesium ions in plants. [1]


(b) Describe the symptoms of magnesium deficiency in a plant. [1]


16. Fig. 16.1 shows a flower.

(Imagine a diagram of a typical insect-pollinated flower with large petals, nectaries, and sticky pollen.)

(a) State two features visible in Fig. 16.1 that suggest this flower is insect-pollinated. [2]



(b) Describe the process of pollination. [2]



17. After fertilisation in a flower, several changes occur.

(a) State what the ovule develops into. [1]


(b) State what the ovary wall develops into. [1]


18. Explain the importance of transpiration pull in tall trees. [2]



19. A student placed a strip of epidermis from a red onion bulb into a concentrated salt solution.

(a) Describe what happens to the cells. [1]


(b) Name the condition of the cells after being in the salt solution. [1]


20. Glucose produced during photosynthesis is often converted into starch for storage.

(a) Explain why glucose is converted into starch for storage rather than kept as glucose. [2]



(b) Describe a simple food test to confirm the presence of starch in a leaf. [2]



*** End of Quiz ***

Answers

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O-Level Biology Quiz - Plant Biology (Answer Key)

Total Marks: 40

Section A: Structured Questions

1. Transpiration [1]

2. Carbon dioxide + Water → Glucose + Oxygen [1]
(Or: 6CO2+6H2OC6H12O6+6O26CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2) [1]
(1 mark for correct reactants, 1 mark for correct products)

3. (a) Palisade mesophyll [1]
(b) Contains many chloroplasts [1] to absorb maximum light energy for photosynthesis [1].
(Alternatively: Columnar shape allows tight packing to absorb more light)

4. (a) Oxygen is a product of photosynthesis [1].
(b) Light intensity decreases as distance increases [1]. Light is a limiting factor for photosynthesis, so the rate decreases [1].

5.

  1. Pollen tube grows from the stigma [1].
  2. Grows down through the style [1].
  3. Enters the ovule through the micropyle [1].
    (Note: Must mention growth direction and entry point)

6. (a) Active transport [1]
(b) It moves ions against the concentration gradient (from low to high concentration) [1], which requires energy from respiration (ATP) [1].

7. (a) Water uptake is approximately equal to water loss by transpiration [1].
(b) Some water is used for photosynthesis / turgidity / kept in cells [1].

8. (a) Phloem [1]
(b) Translocation [1]

9. Xylem vessels are dead / hollow / have lignin thickening / no cytoplasm [1].
(OR Phloem sieve tubes have living cytoplasm / sieve plates / companion cells).
(Accept any valid structural difference)

10. Rate of transpiration exceeds rate of water uptake [1]. Cells lose turgor pressure / become flaccid [1].


Section B: Data Interpretation & Application

11. (a) The rate increases [1] until it reaches a maximum/plateau (saturation point) [1].
(b) Higher temperature increases the kinetic energy of enzymes/substrates [1], leading to more frequent collisions and a faster rate of reaction (up to optimum) [1].
(c) Temperature (or Light Intensity) [1]. (Since CO2 is no longer limiting, another factor is limiting).

12. (a) CO2 is a raw material for photosynthesis [1]. Increasing it increases the rate of photosynthesis, producing more glucose for growth/yield [1].
(b) Light intensity [1] (or Temperature).

13. (a) To reduce water loss by transpiration [1]. The upper surface is exposed to direct sunlight/heat, so having no stomata prevents excessive evaporation [1].
(b) The lower surface is in contact with water [1], so stomata on the upper surface allow gas exchange with the air [1].

14. (a) Rate = Distance / Time [1]
Rate = 10 cm / 30 s = 0.33 cm/s [1].
(b) Wind removes water vapour from around the leaf [1]. This maintains a steep concentration gradient of water vapour between the inside and outside of the leaf [1]. This increases the rate of diffusion of water vapour out of the stomata [1].

15. (a) Formation of chlorophyll [1].
(b) Yellowing of leaves (chlorosis) [1].

16. (a) Any two from: Large/coloured petals [1], Nectaries present [1], Sticky/heavy pollen [1], Scented [1].
(b) Transfer of pollen grains [1] from the anther to the stigma [1].

17. (a) Seed [1]
(b) Fruit (or Pericarp) [1]

18. It pulls water and mineral ions up the xylem [1] from the roots to the leaves against gravity [1].

19. (a) Water leaves the cell by osmosis [1]. (Cytoplasm shrinks/pulls away from cell wall).
(b) Plasmolysed [1].

20. (a) Starch is insoluble [1], so it does not affect the water potential of the cell / does not diffuse out of the cell [1].
(b) Add iodine solution [1]. If starch is present, the colour changes from brown/orange to blue-black [1].