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A Level H2 Chemistry Atomic Structure Bonding Quiz
Free A Level H2 Chemistry Atomic Structure Bonding quiz, HY3 Exam version, with questions, answers, and A Level-style practice for Singapore students.
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A-Level Chemistry H2 Quiz - Atomic Structure Bonding (Answer Key)
Total Marks: 40
Topic: Atomic Structure & Bonding
Section A Answers (5 marks)
Q1. [1 mark]
Answer: 17 electrons.
Teaching note: (^{35}_{17}\text{Cl}) has proton number 17. A neutral atom has electrons = protons = 17. The isotope mass (35 vs 37) changes neutron count only, not electrons.
Q2. [1 mark]
Answer: B (p).
Teaching note: s orbitals are spherical; p orbitals are dumbbell-shaped; d orbitals are cloverleaf-like.
Q3. [1 mark]
Answer: a gaseous atom (or "one mole of gaseous atoms").
Teaching note: First IE = energy to remove 1 electron from each atom in 1 mol of gaseous atoms: (\text{X(g)} \rightarrow \text{X}^+(g) + e^-).
Q4. [1 mark]
Answer: along the axis between (or "directly between").
Teaching note: A σ bond from s–s overlap has cylindrical symmetry about the internuclear axis; electron density is between nuclei.
Q5. [1 mark]
Answer: C (induced dipole–induced dipole / London dispersion).
Teaching note: All molecules exhibit temporary induced dipoles; H-bonding and permanent dipoles require specific conditions.
Section B Answers (20 marks)
Q6. [2 marks]
- Protons: 13 (from Z = 27, Al has Z=13)
- Neutrons: 27 − 13 = 14
- Electrons: 13 − 3 = 10 (3+ charge means loss of 3 e⁻)
Marking: 1 mark for protons/neutrons correct pair, 1 mark for electrons.
Q7. [2 marks]
Answer: (1s^2 2s^2 2p^3)
Teaching note: Z=7 → 7 electrons fill 1s (2), 2s (2), 2p (3). Award 1 mark for correct order, 1 for superscript counts.
Q8. [2 marks]
Shape: trigonal planar
Bond angle: 120°
Teaching note: B has 3 bond pairs, 0 lone pairs → AX₃ → trigonal planar, 120°.
Q9. [2 marks]
Dot-and-cross: O=C=O with double bonds; C shares 4 e⁻ (2 from each O). Expected:
:O::C::O: (using cross for C, dot for O outer e⁻)
Marking: 1 for two double bonds, 1 for correct octets.
Q10. [2 marks]
Answer: N–H bonds are polar (N more electronegative). Molecular shape is trigonal pyramidal (one lone pair on N), so bond dipoles do not cancel → net dipole.
Marking: 1 for shape/lone pair, 1 for non-cancellation.
Q11. [2 marks]
Answer: Delocalised valence electrons in a 'sea' around positive metal ions (Na⁺); electrostatic attraction holds lattice.
Marking: 1 for delocalised electrons, 1 for electrostatic attraction.
Q12. [2 marks]
Bonding: ionic
Conducting particles: Mg²⁺ and O²⁻ (ions)
Marking: 1 each.
Q13. [2 marks]
Answer: H₂O has higher bp than H₂S because H₂O forms hydrogen bonds (O–H), stronger than induced dipoles in H₂S.
Marking: 1 for comparison, 1 for H-bond reason.
Q14. [2 marks]
Answer: C=C is shorter. Higher bond energy means stronger attraction → shorter bond.
Marking: 1 for C=C, 1 for explanation.
Q15. [2 marks]
Answer: Non-polar. C–Cl bonds are polar but tetrahedral shape causes dipoles to cancel.
Marking: 1 for non-polar, 1 for symmetry cancellation.
Section C Answers (15 marks)
Q16. [3 marks]
(a) Group 2 (large jump after 2nd IE). [2 marks]
(b) X²⁺ [1 mark]
Teaching note: Big increase 3rd IE → 2 valence e⁻ removed → Group 2.
Q17. [3 marks]
(a) C–O (ΔEN = 1.0 > C–Cl 0.5 > C–H 0.4). [2 marks]
(b) Cδ+ – Oδ− [1 mark]
Teaching note: Higher EN gets δ−.
Q18. [3 marks]
Answer: C is giant molecular (e.g. diamond) with strong covalent network needing much energy to break; A is simple molecular with weak induced dipoles. [3 marks: 1 structure, 1 forces, 1 comparison]
Q19. [3 marks]
Answer: NH₃ donates lone pair on N to H⁺ (no e⁻); both e⁻ in N–H bond from N. [3: 1 donation, 1 origin, 1 bond formed]
Q20. [3 marks]
Ne high IE (full shell). Na low (new shell, shielding). Mg higher than Na (higher Z, same shell). [3: 1 Ne, 1 Na drop, 1 Mg rise]