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A Level H2 Biology Practice Paper 1
Free A Level H2 Biology Practice Paper 1, Gemma31B Exam version, with questions, answers, and A Level-style practice for Singapore students.
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Answer Key - Biology H2 Practice Paper 1 (Version 1)
Question 1 (a) Inducible operons ensure that enzymes are only synthesized when the specific substrate (e.g., lactose) is present [1]. This prevents the wasteful expenditure of energy and amino acids [1] on producing proteins that have no substrate to act upon [1]. (b) Allolactose acts as an inducer [1]. It binds to the repressor protein [1], causing a conformational change that prevents the repressor from binding to the operator region [1]. (c) -galactosidase would be produced constitutively [1]. Since the repressor cannot bind to the operator, RNA polymerase can transcribe the structural genes regardless of whether lactose is present [1].
Question 2 (a) Oxygen is the final electron acceptor in the ETC [1]. When ADP is present, ATP synthase allows protons to flow back into the matrix [1], which dissipates the proton gradient and allows the ETC to continue pumping protons and consuming oxygen [1]. (b) ATP Synthase (Complex V) [1]. Because the proton gradient remains high but oxygen consumption stops, the "block" is at the end of the process where protons normally exit [1]. (c) ATP synthesis requires the flow of protons through ATP synthase driven by the electrochemical gradient [1]. If the ETC is inhibited or the gradient cannot be dissipated, the phosphorylation of ADP to ATP ceases [1]. No ATP is produced via chemiosmosis [1].
Question 3 (a) An electric field/potential difference is applied across the gel [1]. Proteins migrate through the gel matrix based on their net charge and molecular mass/shape [1]. The gel acts as a molecular sieve [1]. Different variants of hemoglobin have different charges/shapes, causing them to move at different velocities [1]. (b) Heterozygous (HbA/HbS) [1]. Individual B shows two distinct bands [1], indicating the presence of two different hemoglobin alleles, each producing a protein with a different migration distance [1]. (c) A point mutation replaces glutamic acid (polar/negative) with valine (non-polar/hydrophobic) [1]. This changes the overall charge and surface properties of the -globin chain [1], altering its interaction with the gel matrix and its migration speed [1].
Question 4 (a) Misfolding exposes hydrophobic amino acid residues that are normally buried in the protein core [1]. These exposed hydrophobic regions seek to minimize contact with water [1]. They interact with similar regions on other misfolded proteins via hydrophobic interactions, leading to aggregation [1]. (b) Aggregates are insoluble and can physically obstruct cellular transport [1]. They may also sequester essential chaperones or trigger apoptosis/cell death pathways [1]. (c) Chaperones bind to hydrophobic regions of nascent polypeptides [1]. This prevents premature folding or non-specific aggregation [1] and provides a protected environment for the protein to fold into its correct tertiary structure [1].
Question 5 (a) At high temperatures, cholesterol restricts the movement of phospholipids, preventing the membrane from becoming too fluid/leaky [1]. At low temperatures, it prevents phospholipids from packing too tightly [1], preventing the membrane from crystallizing/freezing [1]. (b) Facilitated diffusion is passive (no ATP) [1], while active transport requires ATP [1]. Both use membrane proteins (channels/carriers) [1], but active transport specifically uses carrier proteins (pumps) to move solutes against a concentration gradient [1]. (c) The pump actively transports 3 out and 2 in [1]. This creates a concentration gradient [1]. leak channels allow to leave the cell more easily than enters [1], leaving the interior of the cell negatively charged relative to the exterior [1].