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A Level H1 Biology Practice Paper 5
Free A Level H1 Biology Practice Paper 5, Gemma31B Exam version, with questions, answers, and A Level-style practice for Singapore students.
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Answers
Answer Key - Biology H1 Practice Paper 2 (Version 5)
Question 1 (a) Rough Endoplasmic Reticulum (RER). [1] Role: Synthesis of proteins (specifically secretory proteins/enzymes) for export from the cell. [1] (b) CO₂ is a product of the Krebs cycle/link reaction which occurs in the mitochondrial matrix. [1] Pyruvate can be converted to Acetyl-CoA and enter the Krebs cycle directly. [1] Glucose requires glycolysis to be converted to pyruvate, but glycolysis occurs in the cytoplasm, not the mitochondria; isolated mitochondria lack glycolytic enzymes. [1]
Question 2 (a) Phospholipids form a bilayer. [1] Hydrophilic heads face the aqueous environment (extracellular/cytoplasm) and hydrophobic tails face inward, away from water. [1] (b) Facilitated diffusion. [1] Glucose moves down its concentration gradient through a specific carrier protein (as shown in Fig 2). [1]
Question 3 (i) Period B (S phase). [1] Thymine is a nitrogenous base used specifically in DNA synthesis; S phase is when DNA replication occurs. [1] (ii) In period B, DNA amount doubles due to semi-conservative replication. [1] In period C, DNA amount remains constant. [1] In period D (Mitosis), sister chromatids separate, resulting in the DNA amount per nucleus returning to the original level (halving). [1]
Question 4 (a) Prokaryotes lack a membrane-bound nucleus (circular DNA in cytoplasm) [1], lack membrane-bound organelles (e.g., mitochondria) [1], and are generally much smaller than eukaryotes. [1] (b) "Fluid" refers to the lateral movement of phospholipids and proteins, allowing membrane flexibility and protein movement. [1] "Mosaic" refers to the diverse proteins embedded in the bilayer. [1] This allows for dynamic functions like endocytosis or the movement of receptors to facilitate cell signaling. [1]
Question 5
- Organism X shows peak activity at pH 2.0. [1] The stomach environment is highly acidic (HCl), providing the optimal pH for this protease to maintain its active site shape and catalyze reactions. [1]
- Organism Y shows peak activity at pH 8.0. [1] The small intestine is slightly alkaline, which is the optimal pH for Organism Y's enzyme to function. [1]
- At non-optimal pH, enzymes denature, losing the complementary shape of the active site to the substrate. [1] (Any 4)
Question 6 (a) Consists of one glycerol molecule [1] ester-linked to three fatty acid chains. [1] The bonds are ester bonds. [1] (b) High specific heat capacity: resists temperature changes, providing a stable thermal environment for enzymes. [2] Polarity: allows water to act as a universal solvent for polar/ionic solutes (e.g., glucose, ions) for transport in blood/xylem. [2]
Question 7 (a) DNA double helix unwinds/unzips via helicase. [1] Each original strand acts as a template. [1] DNA polymerase adds complementary free nucleotides. [1] Result is two identical DNA molecules, each with one old and one new strand. [1] (b) Restriction endonucleases cut DNA at specific recognition sites to create "sticky ends" (complementary overhangs). [2] DNA ligase catalyzes the formation of phosphodiester bonds between the gene and the vector, sealing the sugar-phosphate backbone. [2]
Question 8
- CO₂ uptake: Diffusion across stomata and cell membranes down a concentration gradient to provide carbon for the Calvin cycle. [2]
- Water uptake: Osmosis across root cell membranes; essential for photolysis in the light-dependent reaction. [2]
- Ion transport: Active transport of Mg²⁺ (for chlorophyll synthesis) or K⁺ (for stomatal opening). [2]
- Product export: Facilitated diffusion/transport of sucrose out of the chloroplast/cell to be translocated. [2] (Max 6)
Question 9 (a) DNA replication in S phase ensures two identical copies of each chromosome. [1] Alignment of chromosomes at the metaphase plate. [1] Separation of sister chromatids by spindle fibers. [1] Each daughter cell receives an identical set of chromosomes. [1] (b) Growth: Ensures new cells are functionally identical to original cells for tissue expansion. [1] Repair: Replaces damaged cells with identical versions to maintain organ function. [1] Asexual reproduction: Produces genetically identical clones. [1]
Question 10 (a) Primary: Linear sequence of amino acids in a polypeptide chain. [1] Tertiary: The overall 3D folding/shape of the protein. [2] (b) A change in amino acid sequence (mutation) [1] can alter the R-group interactions (e.g., hydrogen bonds, disulfide bridges), changing the 3D shape of the active site/binding site. [1] This prevents the substrate from binding, rendering the protein non-functional. [1]